Java collections

Hard Prerequisites
  • PROJECTS: Animals
  • TOPICS: Java collections and data structures
  • Soft Prerequisites
  • TOPICS: Intro to Docker and Docker-compose
  • TOPICS: Introduction to Gradle
  • PROJECTS: Dice
  • PROJECTS: Person

  • This project assumes you have gone through the reading for both data structures as well as collection, but for a quick recap for the purpose of this project:

    Java has a collection framework that gives us a list of classes which help us efficiently deal with objects, one of these is called a dequeue/deque(double-ended queue). A deque is magical because it allows us to add or remove anything from either the front(head) or back(tail) of the queue.

    You can implement a Deque by using either a LinkedList of an ArrayDeque class. For example

    Deque queue = new LinkedList<>();
    or
    Deque queue = new ArrayDeque<>();
    

    Now for the FUN part… Project time

    intNumber = 9 // Number of integer in the set
    subArraySize = 3 // Size of the subArray to consider
    queue = 6 2 6 8 3 7 1 4 4 // integer sample
    

    You have to print out the maximum number of unique integers among all possible adjacent subarrays of size subArraySize

    Example of the project

    Input

    intNumber = 9
    subArraySize = 3
    queue = 6 2 6 8 3 7 1 4 4
    

    Output

    3

    Explanation

    r1 => (6 2 6) = Has 2 unique numbers
    
    r2 => (2 6 8) = Has 3 unique numbers
    
    r3 => (6 8 3) = Has 3 unique numbers
    
    r4 => (8 3 7) = Has 3 unique numbers
    
    r5 => (3 7 1) = Has 3 unique numbers
    
    r6 => (7 1 4) = Has 3 unique numbers
    
    r7 => (1 4 4) = Has 2 unique numbers
    

    So the highest number of unique integer in a subArray is 3

    If your code is correct it should return these outputs for these inputs

    Input #1

    intNumber = 8
    subArraySize = 4
    queue = 2 2 2 2 2 2 2 2
    

    Output

    1
    

    Input #2

    intNumber = 10
    subArraySize = 3
    queue = 7 5 5 7 5 5 7 5 5 6
    

    Output

     2
    

    HAVE FUN!!


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